50 grams of ice at 0 °C is mixed with 40 gm of water at 60°C . Then the ratio of ice and water at equilibrium is

Principle of method of mixtures

$\text{ Heat lost By }40 \mathrm{g}\text{ water }=\text{ Heat used in melting }\mathrm{x}\text{ gram of ice}$

$\Rightarrow 40\times 1\times 60=\mathrm{x}\times 80$

$\Rightarrow \mathrm{x}=30 \mathrm{g}$

$\text{Water mass finally in mixture }=40+30 \mathrm{g}=70 \mathrm{g}$

$\text{Ice left }=50-30 \mathrm{g}=20 \mathrm{g}$

$\text{ Ratio of ice to water }=20:70=2:7$