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50 milliliters of CO is mixed with 20 mL of oxygen and sparked. After the reaction, the
mixture is treated with an aqueous KOH solution. Choose the correct answer option.

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The volume of the CO that reacts = 40 mL

The volume of the ${CO}_{2}$ formed = 40 mL

The volume of the CO that remains after treatment with KOH = 10 mL

The volume of the CO that remains after treatment with KOH = 20 mL

answer is A, B, C.

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Detailed Solution

The reaction is $\underset{\underset{40.0 mL}{2 Vol}}{{2CO}_{(g)}} + \underset{\underset{20.0 mL}{1 Vol}}{O_{2 (g)}} \to \underset{\underset{40.0 mL}{2 Vol}}{{2CO}_{2 (g)}}$

Volume of CO(g) that reacts = 40.0 mL

Volume of ${CO}_{2} (g)$ formed = 40.0 mL

Volume of CO(g) removed after treatment with KOH = 50mL – 40mL = 10.0mL

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