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50 ml 0.1 M $N H_{4} O H$ is mixed with 25 ml of $0.1 M H C l .$ p^H of the mixture is
$(K_{b} o f N H_{3} = 1.8 \times 10^{- 5}; \log 1.8 = 0.25)$

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10.25

9.25

5.75

3.75

answer is C.

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Detailed Solution

$p^{k_{b}} = 5 - \log 1.8 = 4.75$
$\begin{array}{l} V_{b} N_{b} = 5 m e q \\ V_{a} N_{a} = 2.5 m e q \end{array}$
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$\begin{array}{l} p^{O H} = 4.75 + \log \frac{2.5}{2.5} = 4.75 \\ p^{H} = 14 - 4.75 = 9.25 \end{array}$

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