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Q.

50 mL of 0.2 molal urea solution (density = 1.012 g mL–1 at 300 K) is mixed with 250 mL of a solution containing 0.06 g of urea. Both the solutions were prepared in the same solvent. The osmotic pressure (in torr) of the resulting at 300 K is ____.
[Use : Molar mass of urea = 60 g mol–1; gas constant, R = 62 L torr K–1 mol–1;
Assume, mix H = 0, mix V = 0]

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answer is 682.

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Detailed Solution

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solution-I 50ml, 0.2 molal urea solution with density 1.012 g/L of solution wt of solution =50.6 gram Let urea = x gram 
Solvent = (50.6-x) gram  
Molality = x×100060×(50.6x)
0.2=1000x60×50.6x
X=0.6gram
Solution II-  0.06 gram urea in 250ml. solution
Total wt of urea =0.6+0.06
 = 0.66gram
Total volume =50+250  =300ml
π=C.RT=0.66×100060×300×62×300=682 torr 

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50 mL of 0.2 molal urea solution (density = 1.012 g mL–1 at 300 K) is mixed with 250 mL of a solution containing 0.06 g of urea. Both the solutions were prepared in the same solvent. The osmotic pressure (in torr) of the resulting at 300 K is ____.[Use : Molar mass of urea = 60 g mol–1; gas constant, R = 62 L torr K–1 mol–1;Assume, ∆mix H = 0, ∆mix V = 0]