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Q.

50 mL of 0.5 M oxalic acid is needed to neutralize 25 mL of sodium hydroxide solution. The amount of NaOH in 50 mL of the given sodium hydroxide solution is :

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a

4 g

b

10 g

c

20 g

d

80 g

answer is A.

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Detailed Solution

I H2C2O4
  Va = 50ml
  Ma = 0.5M
  na = 2
  NaOH
  Vb = 25ml
  nb = 1

Nb = ?
  VaNa = VbNb
50(0.5)2 = 25(Nb)
  Nb = 2N
II VNaOH  solution = 50ml
   

\large N\; = \;\frac{w}{{GEW}} \times \frac{{1000}}{v}


  

\large 2\; = \;\frac{w}{{40}} \times \frac{{1000}}{{50}}


WNaOH  = 4g

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