Q.

50 ml of a gaseous mixture of hydrogen and hydrogen chloride was exposed to sodium amalgam. The volume decreased to 40 ml. If 10 ml of the same mixture is mixed With 6 ml of gaseous ammonia and then exposed to water, what will be the final volume (in ml) of gas left? All the volumes are measured at the same temperature and pressure.

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answer is 6.

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Detailed Solution

2Na+2HCl2NaCl+H2

2a+b = 50

a+b = 40  2a =20 ml HCI  b = 30 ml H2

50ml20mlHCl+30mlH210ml4mlHCl+6mlH2HCl+NH3NH4Cl

Hence, 6 ml H2 is left.

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