50% of X-rays obtained from a Coolidge tube pass through 0.3 mm, thick aluminum foil. If the potential difference between the target and the cathode is increased, then the fraction of X-rays passing through the same foil will be:

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50%

> 50 %

< 50 %

0 %

answer is B.

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Detailed Solution

Concept: To answer this topic, we must first comprehend the notion of a Coolidge tube, also known as a cathode tube. Then we will compare all of the available possibilities to arrive at the correct solution.
We know that increasing the accelerating potential between the filament and the target increases the X-penetrating ray's power. As a result, the percentage of X-rays flowing through the foil would increase.
The Coolidge tube is the predecessor of all X-ray tubes now in use. The Coolidge tube was the first practical form of x-ray tube to utilize the notion of thermionic emission.
The penetrating intensity of X-rays is directly proportional to the electrons' (V) accelerating potential or the X-ray energy.
However, it is assumed that the same proportion of X-ray is passing. As a result, the thickness of the aluminum foil should be raised to keep the same proportion of the X-ray passing through the foil.
As a result, we infer that increasing the potential difference between the target and the cathode increases the proportion of X-rays flowing through the same foil to greater than 50%.
Hence, the correct option is 2.

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