Q.

500 J of energy is transferred as heat to 0.5 mol of Argon gas at 298 K and 1.00 atm. The final temperature and the change in internal energy respectively are :
Given : R = 8.3 J K–1 mol–1

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a

348 K and 300 J

b

368 K and 500 J

c

378 K and 500 J

d

378 K and 300 J

answer is D.

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Detailed Solution

qp=n×cp×ΔT500=0.5×52×8.3Tf298Tf346.2KΔHΔU=CpCv=53ΔU=35×500=300J

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