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Q.

500 J of energy is transferred as heat to 0.5 mol of Argon gas at 298 K and 1.00 atm. The final temperature and the change in internal energy respectively are :
Given : R = 8.3 J K^–1 mol^–1

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a

348 K and 300 J

b

368 K and 500 J

c

378 K and 500 J

d

378 K and 300 J

answer is D.

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Detailed Solution

$\begin{array}{l} q_{p} = n \times c_{p} \times ΔT \\ \Rightarrow 500 = 0.5 \times \frac{5}{2} \times 8.3 (T_{f} - 298) \\ \Rightarrow T_{f} ≃ 346.2 K \\ \frac{ΔH}{ΔU} = \frac{C_{p}}{C_{v}} = (\frac{5}{3}) \\ \Rightarrow ΔU = \frac{3}{5} \times 500 = 300 J \end{array}$

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