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Q.

500 ml of 0.1 M CuSO4 solution is electrolyzed for 5 min at a current of 0.161 A. If Cu is produced at one electrode and oxygen at the other, then what is pH of final solution? Report the value to nearest integer

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answer is 3.

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Detailed Solution

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H+final=5×10−4500×1000=10−3M⇒pH=3.0

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