500 ml of 2 M HCl and 500 ml of 1 M NaOH are mixed with each other. Proton concentration of the resultant mixture is ----- M

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0.6

0.7

0.5

0.4

answer is C.

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Detailed Solution

$V_{a} N_{a} = 500 (2) 1; V_{b} N_{b} = 500 (1) 1; V_{a} N_{a} > V_{b} N_{b}; N = {[H]}^{+} = \frac{V_{a} N_{a} - V_{b} N_{b}}{Total volume of the mixture}; N = {[H]}^{+} = \frac{1000 - 500}{1000} N = 0.5 N;$

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