AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

500 ml of a waste solution obtained from a factory contains 0.5M $C u S O_{4}$ and 0.5M $Z n {(N O_{3})}_{2}$ The solution was electrolyzed at 6v by passing a current of 10A for 60 minutes. The metal/metals electrodeposited will be:
$(E_{c u^{2 +} / c u}^{0} = 0.34 V, E_{z n^{2 +} / z n}^{0} = - 0.76 V)$

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

only Zn

Zn and Cu in equal mass proportion

Zn and Cu in proportion to their atomic mass

only Cu

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

Amount of charge used =10×60×60=36000C=0.373F
Amount of $c u^{+ 2}$ available =0.5×0.5=0.25 mole
Amount of charge required to deposit all $c u^{+ 2}$ =0.5F
only $c u^{+ 2}$ will be deposited(partially), $z n^{+ 2}$ will not discharge

Watch 3-min video & get full concept clarity

courses

No courses found

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!