5.00 moles of hydrogen gas, 3 moles of white phosphorus {${\mathrm{P}}_4\left(\mathrm{s}\right)$) and 12 moles of oxygen gas are taken in a sealed flask and allowed to react as follows ${\mathrm{H}}_2\left(\mathrm{g}\right)+{\mathrm{P}}_4\left(s\right)+{\mathrm{O}}_2\left(\mathrm{g}\right)⟶{\mathrm{H}}_3{\mathrm{PO}}_4$

Determine the moles of ortho-phosphoric acid that can be produced, considering that the reaction occurs in 90% yield.