52,32,72,95,98arrange the following in descending order. Thedescending order is 72,52,95,32,98.

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The statement is true.Concept: The  descending order is 72,52,95,32,98. Take the L.C.M. of all the supplied rational numbers for the denominators. To make the denominator of each rational number equal the L.C.M., multiply the numerator and denominator of each rational number by a certain value. Check the numerators of the resulting fractions once each fraction's denominator has become the same. Sort the fraction from the fraction with the highest numerator to the fraction with the lowest numerator in order to write it in decreasing order.The following fractions have been given to us :52,32,72,95,98.These fractions must be arranged in descending order, with the fraction with the highest value written first and the fraction with the lowest value written last. We can observe that the first three fractions in the list above have the identical denominators. So it is simple to arrange them in descending order. The next two fractions, however, have different denominators, making it difficult to arrange them in the proper sequence. Therefore, we must first equalise the denominators of all the fractions.Now that we are aware of the denominators, 2, 5, and 8, Their L.C.M will be 40 as a result. We must now change each fraction's denominator to 40. Thus, the various fractions can be expressed as follows:1 ) 52=52×2020=100402) 32=32×2020=60403) 72=72×2020=140404) 95=95×88=72405 ) 98=98×55=4540Now, since the denominator of each term is 0. Therefore, now we have to check the numerator.Arranging the terms having numerator greatest to smallest, we have,14040,10040,7240,6040,4540 Now, equating their original form, we get,72,52,95,32,98So, the correct answer is 72,52,95,32,98.Hence, the answer is option 1) true.

$\frac{5}{2}, \frac{3}{2}, \frac{7}{2}, \frac{9}{5}, \frac{9}{8}$ arrange the following in descending order. Thedescending order is $\frac{7}{2}, \frac{5}{2}, \frac{9}{5}, \frac{3}{2}, \frac{9}{8}$ .

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