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56 gram of N₂ and 96 gm of O₂ are mixed isothermally and at a total pressure of 10 atm. The partial ressures of O₂ and N₂ (in atm) are respectively

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8, 2

5, 5

2, 8

6, 4

answer is D.

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Detailed Solution

$\begin{array}{l} P_{N_{2}} = \frac{n_{N_{2}}}{n_{N_{2}} + n_{O_{2}}} \times P_{T} \\ = \frac{56 / 28}{56 / 28 + 96 / 32} \times 10 = 4 atm \\ P_{O_{2}} = 10 - 4 = 6 atm \end{array}$

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