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5.6 lit of gas SO_x at 1 atm and 273K weighs 20 gms. X value and molar mass of gas respectively is

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x = 2; Molar mass = 80 u

x = 3; Molar mass = 64 u

x = 2; Molar mass = 64 u

x = 3 ; molar mass = 80 u

answer is B.

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Detailed Solution

molar mass = $\frac{20 \times 22.4}{5.6} = 80$

32 + 16X = 80

X = 3

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