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56.0 L of nitrogen gas is mixed with excess of hydrogen gas and it is found that 20 L of ammonia gas is produced. The volume of unused nitrogen gas is found to be____ L.

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answer is 46.

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Detailed Solution

Given:

Initial volume of nitrogen gas: 56.0 L
Volume of ammonia gas produced: 20.0 L

Calculation:

Determine the volume of nitrogen gas that reacted:

According to the stoichiometric ratio, 2 volumes of ammonia are produced from 1 volume of nitrogen gas.
Therefore, the volume of nitrogen gas that reacted is half of the volume of ammonia produced:

46 L

56 - 20 * (1 / 2)=46

Calculate the volume of unused nitrogen gas:

Subtract the volume of reacted nitrogen gas from the initial volume:

Final Answer

The volume of unused nitrogen gas is 46.0 L.

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