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Q.

56.0 L of nitrogen gas is mixed with excess of hydrogen gas and it is found that 20 L of ammonia gas is produced. The volume of unused nitrogen gas is found to be------ L.

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answer is 46.

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Detailed Solution

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From the stoichiometry for 2L production of ammonia 1L of $N_{2}$ gas is used.

The volume of unused $N_{2} = 56 - 10 = 46 L$

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