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Q.

5.6g of an organic compound on burning with excess of oxygen gave 17.6 g of CO2 and 7.2 g H2O. The organic compound is

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a

C6H6

b

CH3COOH

c

C4H8

d

C3H8

answer is B.

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Detailed Solution

Moles of CO2:

Moles=17.6 g44 g/mol=0.4 mol

Moles of H2O:

Moles=7.2 g18 g/mol=0.4 mol

General combustion reaction:

CxHy+12x+y2O2xCO2+y2H2O

Hence, x is 0.4 and y is 0.8; formula becomes C4H8.

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