$58.5\mathrm{g}\text{ of }\mathrm{NaCl}\text{ and }180\mathrm{g}$ of glucose were separately dissolved in $1000 \mathrm{mL}$ of water. Identify the correct statement regarding the elevation of boiling point (b.pt.) of the resulting solutions 

$\mathrm{\Delta }{T}_b=i{K}_{b}m$

For water $\Rightarrow 1000\mathrm{mL}=1000\mathrm{g}$

Molality of$\mathrm{NaCl}=\frac{\mathrm{wt}.\left(\mathrm{solute}\right)/\mathrm{M}}{\mathrm{W}\left(\text{ solvent }\right)}\times 1000$

                          $=\frac{58.5/58.5}{1000}\times 1000=1\mathrm{m}$

Molality of glucose $=\frac{180/180}{1000}\times 1000=1\mathrm{m}$

For NaCl, i=2 and 

For glucose, i=1

$\therefore$$\mathrm{\Delta }{T}_b\text{ for }\mathrm{NaCl}>\mathrm{\Delta }{T}_b$ for glucose