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s$ , what distance will it cover before coming to rest?

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405 m

406 m

408 m

None

answer is A.

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Detailed Solution

The distance covered before coming to rest is

405 m .

Given that,
Uniform retardation

a = - 0.9 m / s^{2}

Initial velocity,

u = 27 m / s

Final velocity,

v = 0 m / s

Distance covered,

s

is unknown
We know the equation,

v^{2} - u^{2} = 2 as

To find out the distance covered, substitute the values in the equation.

v^{2} - u^{2} = 2 as

\Rightarrow 0 - {(27)}^{2} = 2 \times (- 0.9) \times s

Distance covered

s = 405 m

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