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Q.

5g of Na₂SO₄ was dissolved in x g of H₂O. The change in freezing point was found to be 3.82^oC. If
Na₂SO₄ is 81.5% ionized, the value of x (K_f for water = 1.860^oC kg mol^-1) is approximately:

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a

45g

b

65g

c

25g

d

15g

answer is A.

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Detailed Solution

$∆$ T_f = ik_fm

3.82 = 1+0.815(3-1)[ $\frac{5}{142} \times \frac{1000}{x g m}$ ] $\times$ 1.86

x = 45. gm

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5g of Na2SO4 was dissolved in x g of H2O. The change in freezing point was found to be 3.82oC. IfNa2SO4 is 81.5% ionized, the value of x (Kf for water = 1.860oC kg mol-1) is approximately: