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$5 g$ of zinc is treated separately with an excess of
a) dilute hydrochloric acid and
b) aqueous sodium hydroxide
The ratio of the volumes of $H_{2}$ evolved in these two reactions is

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$1 : 2$

$1 : 4$

$2 : 1$

$1 : 1$

answer is A.

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Detailed Solution

Zinc reaction with dilute hydrochloric acid

$Z n + 2 H C l ⟶ {Z n C l}_{2} + H_{2}$

Zinc reaction with aqueous sodium hydroxide.

$Z n + 2 N a O H ⟶ {N a}_{2} {Z n O}_{2} + H_{2}$

Compairing both the equation since coefficients of reactants and products are same providing same amount of zinc will produce same amount of hydrogen gas

Thus The ratio of the volumes of $H_{2}$ evolved in these two reactions. Is 1:1

Hence option (A) is the correct answer.

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