$6.023\times {10}^{20}$ molecules of urea are present in 100ml of its solution. The concentration of solution is

$6.023\times {10}^{23}$urea molecule $\omega t=60\left(N{H}_{2}CON{H}_2\right)$
$6.023\times {10}^{20}$urea molecule $\omega t=?$
$=\frac{\cancel{6.023}\times {10}^{20}\times 60}{\cancel{6.023}\times {10}^{23}}=60\times {10}^{-3}=6\times {10}^{-2}gm$
$M=\frac{\omega }{G.M.\omega }\times \frac{1000}{V}=\frac{6\times {10}^{-2}}{60}\times \frac{1000}{100}={10}^{-2}M=0.01M$