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Q.

6.8 gm of H2O2 is present in 500 ml of an aqueous solution. When 10ml of this solution is decomposed, what is the S.T.P. volume of oxygen obtained

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a

560 ml

b

11.2 lit.

c

44.8 ml

d

22.4 ml

answer is C.

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Detailed Solution

large begin{array}{l} M; = ;frac{{Wt}}{{MWt}}; times ;frac{{1000}}{{V(in;ml)}}\ ;;;;;; = ;frac{{6.8}}{{34}}; times ;frac{{1000}}{{500}} end{array}
M = 0.4M
volume strength = M x 11.2
                       = 0.4 x 11.2
                       = 4.48
4.48 volume strength of H2O2 means
1ml of H2O2 solution gives → 4.48ml of,O2
10ml of H2O2 solution gives → ??ml  of O2
large frac{10times 4.48}{1}=44.8ml

Therefore 10ml, 4.48(W/V%) volume strength of H2O2 solution gives 44.8ml of O2 at STP.

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