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Q.

6 cells each of emf 1.5 V and internal resistance 1Ω are connected in series. One of the cell is joined with reverse polarity and whose combination is connected across a load resistance. The effective emf and internal resistance (across load resistance) are

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a

6V,6Ω

b

9V,6Ω

c

6V,4Ω

d

6V,4.5Ω

answer is B.

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Detailed Solution

Eeff=(n2m)E=(62×1)E=4E =4×1.5=6V
Reff=r1+r2r6=6Ω

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