6 Coins are tossed 320 times. The probability of getting 5 heads 2 times is

Let X be the number of times of getting 5 heads when tossing 6 coins
Probability of getting 5 heads when tossing 6 coins $=\frac{{ }^6{C}_5}{2^6}=\frac{3}{32}.$
Mean of X is  $320\left(\frac{3}{32}\right)=30.$
Assume that   follows Poisson distribution with parameter  $\lambda .$ Then $\lambda =30,P(X=2)=\frac{e^{-30}{30}^2}{2!}$