6 g of urea (molar mass= $60 g {mol}^{- 1}$ ) and 9 g of glucose (molar mass = $180 g {mol}^{- 1}$ ) were dissolved in 35 g of water. The mass percent of urea and glucose is respectively

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6, 9

12,18

9,6

18, 12

answer is C.

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Detailed Solution

$Mass % = \frac{Mass of component in solution}{Total mass of solution} \times 100 Mass % of urea = \frac{6 g}{41 g} \times 100 ≅ 12 % Mass % of glucose = \frac{9 g}{44 g} \times 100 ≅ 18 %$

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