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6 men can do a piece of work in 16 days. How many days are needed to complete the work if 8 men are engaged in the same work?

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answer is A.

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Detailed Solution

M₁ =6, D₁= 16

M₂=8 , D₂ =x

M₁D₁= M₂D₂

$6 \times 16 = 8 \times D_{2}$

$D_{2} = \frac{6 \times 16}{8}$

$D_{2} = 12 Days$

8 Men will take 12 days.

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