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Q.

60 gm of an organic compound containing C, H, and O atoms on complete combustion gave 88 gm ${CO}_{2}$ and $36 gm$ $H_{2} O$ . The empirical formula of the organic compound is :

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a

$C_{2} HO$

b

$CHO$

c

${CH}_{2} O$

d

${CHO}_{2}$

answer is C.

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Detailed Solution

$\begin{array}{l} n_{c} = \frac{88}{44}; n_{h} = \frac{36}{18} \times 2 \\ = 2 = 4 \end{array}$

Only C in option $C : H :: 1 : 2$

Thus, the empirical formula of the organic compound is ${CH}_{2} O$ .

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