60 gms of lime stone on heating produced 22 gms ofCO2. The percentage of CaCO3 in limestone is

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60 gms of lime stone on heating produced 22 gms of ${CO}_{2}$ . The percentage of ${CaCO}_{3}$ in limestone is

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83.3%

87.66%

60%

80%

answer is C.

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Detailed Solution

${CaCO}_{3} \to CaO + {CO}_{2}$

1 mole ${CO}_{2} = 1 mole {CaCO}_{3}$

$\frac{1}{2} m o l e C O_{2} = 22 g r a m s C O_{2} = 50 g r a m s C a C O_{3}$

Mass of impure ${CaCO}_{3}$ unreacted = 60 − 50 = 10 grams

$% {CaCO}_{3} = \frac{50}{60} \times 100 = 83.3 %$

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