600 c.c. of a gas at a pressure of 750 mm of Hg is compressed to 500 c.c. Taking the temperature to remain constant, the increase in pressure, is

Given initial volume (V1₎ = 600 c.c.; Initial pressure (P₁) = 750 mm of Hg and final volume (V₂) = 500 c.c. according to Boyle’s law,

${\mathrm{P}}_1{\mathrm{V}}_1={\mathrm{P}}_2{\mathrm{V}}_2$

$\text{ or }750\times 600={\mathrm{P}}_2\times 500$

$\text{ or }{\mathrm{P}}_2=\frac{750\times 600}{500}=900\mathrm{mm}\text{ of }\mathrm{Hg}$

Therefore increase of pressure = (900 – 750) = 150 mm of Hg