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$600 J$ of heat is added to a monoatomic gas in a process in which the gas performs a work of $150 J$ . The molar heat capacity for the process is

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$3 R$

$4 R$

$2 R$

$6 R$

answer is C.

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Detailed Solution

$Δ U = Q - W = 450 J = n C_{j} Δ T$

$= n (\frac{3}{2} R) Δ T$

$∴ n Δ T = (\frac{300}{R})$

$Now, C = \frac{Q}{n Δ T}$

$= \frac{600}{300 / R} = 2 R$

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