Q.

600ml of 0.01M HCl is mixed with 400ml of 0.01 M  H2SO4 .The pH of the mixture is ___________ ×10-2 (Nearest integer)
 [Given log 2 = 0.30          log 3 = 0.48          log 5 = 0.69
log 7 = 0.84          log 11 = 1.04]

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answer is 186.

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Detailed Solution

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H(N)=N1V1+N2V2Totalvolume=0.01×1×600+0.01×2×4001000=141000=14×103pH=log7×2×103=3(log7+log2)=3(0.84+0.3)=1.86=186×102

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