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Q.

$60$ gm of Urea $(Mol . wt 60)$ was dissolved in $9.9 moles$ , of water. If the vapour pressure of pure water is $P_{0}$ , the vapour pressure of solution is

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a

$0.99 P_{0}$

b

$1.10 P_{0}$

c

$0.10 P_{0}$

d

$0.90 P_{0}$

answer is C.

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Detailed Solution

$\begin{array}{l} \frac{P^{0} - P_{s}}{P^{0}} = \frac{n}{N} \Rightarrow \frac{P^{\circ} - P_{s}}{P^{\circ}} = \frac{1}{9.9} \Rightarrow 9.9 P^{\circ} - 9.9 P_{s} = P^{\circ} \\ 8.9 P^{\circ} = 9.9 P_{s} \Rightarrow P_{s} = \frac{8.9}{9.9} P^{\circ} \approx 0.90 P^{\circ} \end{array}$

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60 gm of Urea (Mol. wt 60) was dissolved in 9.9 moles, of water. If the vapour pressure of pure water is P0 , the vapour pressure of solution is