60W-220V and 100W-220V bulbs are connected in series to 220V mains. The power consumption is more in the bulb of :

For the given bulbs, resistances will be 

$P =\frac{V^2}{R}$

$60 =\frac{{220}^2}{R_1}\Rightarrow R_1=\frac{4840}{6}\Omega$

$100 =\frac{{220}^2}{R_2}\Rightarrow R_2=484\Omega$

For a series connection, power consumption is

$P=i^{2}R$

$\Rightarrow P\propto R$

Therefore bulb 1 will  consume more power.