−6, −112, −5, ⋯ are in A.P., then t5=

a=−6d=−112−(−6)=−112+6=12t5=a+4d=−6+4×12=−6+2=−4.

−6, −112, −5, ⋯ are in A.P., then t5=

a=−6d=−112−(−6)=−112+6=12t5=a+4d=−6+4×12=−6+2=−4.

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$- 6, \frac{- 11}{2}, - 5, \dots$ are in A.P., then $t_{5} =$

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Detailed Solution

$a = - 6$

$d = \frac{- 11}{2} - (- 6)$

$= \frac{- 11}{2} + 6$

$= \frac{1}{2}$

$t_{5} = a + 4 d$

$= - 6 + 4 \times \frac{1}{2}$

$= - 6 + 2$

$= - 4$ .

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−6, −112, −5, ⋯ are in A.P., then t5=

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$- 6, \frac{- 11}{2}, - 5, \dots$ are in A.P., then $t_{5} =$