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Q.

64 drops of mercury each charged to a potential of 10V are combined to form one bigger drop. The potential of this drop will be (Assume all the drops to be spherical):

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a

10 V

b

80 V

c

160 V

d

640 V

answer is A.

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Detailed Solution

$V = n^{2 / 3} v = (64)^{2 / 3} \times 10 = 160 volt$

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64 drops of mercury each charged to a potential of 10V are combined to form one bigger drop. The potential of this drop will be (Assume all the drops to be spherical):