64 g of an organic compound has 24 g carbon and 8 g hydrogen and the rest is oxygen. The empirical formula of the compound is :

Given,

Organic compound of 64 g

carbon has 24 g

hydrogen has 8 g

$\begin{array}{l}\frac{24}{12}:\frac{8}{1}:\frac{32}{16}\\ 2:8:2\\ 1:4:1\end{array}$

Thus, the empirical formula of the compound is ${\mathrm{CH}}_4\mathrm{O}$