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66640 Pa pressure is exerted by $0.50 m$ vertical column of a liquid. If $g = 9.8 {m/s}^{2}$ , density of the liquid is

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13600 kg m^{- 3}

13600 g {cm}^{- 3}

3600 kg m^{- 3}

4800 kg m^{- 3}

answer is B.

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Detailed Solution

P = h ρ g

$66640 = 0 .5 \times ρ \times 9 .8$

$ρ = \frac{66640}{0.5 \times 9.8} = 13600 {kg/m}^{3}$

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