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6gm of nitrogen on successive reaction with different compounds gets finally converted into 30 gm $[Cr ({NH}_{3})_{x} {Br}_{2}]$ . Value of x is :
[Atomic mass of Cr=52 ]

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$\frac{6}{14} = \frac{30}{M} \times x$

$\begin{array}{l} \Rightarrow M = 70 x \\ 52 + 17 x + 160 = 70 x \\ x = 4 \end{array}$

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6gm of nitrogen on successive reaction with different compounds gets finally converted into 30 gm [Cr(NH3)xBr2]. Value of x is :[Atomic mass of Cr=52 ]

Unlock the full solution & master the concept.

Ready to Test Your Skills?

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6gm of nitrogen on successive reaction with different compounds gets finally converted into 30 gm $[Cr ({NH}_{3})_{x} {Br}_{2}]$ . Value of x is :
[Atomic mass of Cr=52 ]