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7 mol of a certain monoatomic ideal gas undergoes a temperature increase of 40 K at constant pressure. The increase in the internal energy of the gas in this process is :
(Given $R = 8 .3 {JK}^{- 1} {mol}^{- 1})$

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An Intiative by Sri Chaitanya

3486 J

5810 J

11620 J

6972 J

answer is B.

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Detailed Solution

$\begin{array}{l} ΔU = {nC}_{v} ΔT \\ = 7 \times \frac{3 R}{2} \times 40 \\ = 3486 J \end{array}$

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