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Q.

76 grams of Fluorine contains

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a

4 gram atoms of fluorine

b

All the above

c

$12 \times 10^{23} fluorine molecules$

d

2 moles of fluorine

answer is D.

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Detailed Solution

$76 gram F_{2} = \frac{76}{38} = 2 mole F_{2} = 12 \times 10^{23} F_{2} molecules = 4 mole F atoms$

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