Q.

 7C1 7C1+7C2, 7C2 7C2+7C3, 7C3 7C3+7C4 are in 

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a

AP

b

BAP

c

HP

d

GP

answer is A.

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Detailed Solution

 7C1 7C1+7C2=14 7C1 8C2=14 7C182 7C1=14,  7C2 7C2+7C3=38, 7C3 7C3+7C4=12  14,38,12 are in A.P

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 7C1 7C1+7C2,   7C2 7C2+7C3,   7C3 7C3+7C4 are in