8 g of O₂has the same number of molecules as:

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28 g of CO

11 g of CO₂

14 g of CO

7 g of CO

answer is A, D.

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Detailed Solution

Moles of O₂= 8 /32 =0.25 moles

No. of molecules =No. of moles × NA.

Thus, no. of moles is directly proportional to no. of molecules.

Moles of 7 gm CO= 7/28 =0.25

Moles of 14 gm CO= 14 /28 =0.5

Moles of 22 gm CO2= 22 /44 =0.5

Moles of 11 gm of CO₂ =11/44 =0.25

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