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Q.

80 mole percent of ${MgCl}_{2}$ is dissociated in aqueous solution. The vapour pressure of 1.0 molal aqueous solution of ${MgCl}_{2}$ at 38°C ________mm Hg. (Nearest integer)
Given : Vapour pressure of water at 38°C is 50 mm Hg

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answer is 48.

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Detailed Solution

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$i = 1 - α + α + 2 α = 1 + 2 α = 1 + 2 \times 0.8 = 2.6 P^{0} = 50 \frac{P^{0} - P}{P^{0}} = \frac{in}{in + N} \frac{P}{P^{0}} = \frac{N}{in + N} \Rightarrow \frac{P^{0}}{P} = \frac{in}{N} + 1 = \frac{50}{P} = \frac{2.6 \times 1}{\frac{1000}{18}} + 1 = 1.0468 P = \frac{50}{1.0468} = 47.76 ≃ 48 . mm Hg .$

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