80 railway wagons all of same mass 5×103 kg is pulled by an engine with a force of 4×105 N. The tension in the coupling between 30th and 31st wagon from the engine is __ ×105N

F=4×105N,M=80×5×103=4×105kga=4×1054×105=1m/s2T=50×5×103×1=25×104=2.5×105

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80 railway wagons all of same mass $5 \times 10^{3}$ kg is pulled by an engine with a force of $4 \times 10^{5}$ N. The tension in the coupling between 30th and 31st wagon from the engine is __ $\times 10^{5}$ N

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answer is 2.5.

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Detailed Solution

$\begin{array}{l} F = 4 \times 10^{5} N, M = 80 \times 5 \times 10^{3} \\ = 4 \times 10^{5} kg \\ a = \frac{4 \times 10^{5}}{4 \times 10^{5}} = 1 m / s^{2} \\ T = 50 \times 5 \times 10^{3} \times 1 \\ = 25 \times 10^{4} \\ = 2.5 \times 10^{5} \end{array}$

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