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[88]
The value of $g$ above the earth’s surface is [[1]] proportional to the square of distance from the centre of the earth.

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Detailed Solution

The value of

g

is inversely proportional to the square of distance from the centre of the earth. The relation between acceleration due to gravity,

g

, mass of the earth,

M

, and the distance from the centre of the earth to the surface,

r

is given below.

g = \frac{G \times M}{r^{2}}

G

, the universal gravitation constant and

M

are constants.
So we have,

g \propto \frac{1}{r^{2}}

As we go up the surface of the earth, the distance from the centre of the earth increases and hence the value of

g

decreases.

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