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8g of NaOH is dissolved in 18g of H₂O. Mole fraction of NaOH in solution and molality '(in mol kg^-1 ) of the solutions respectively are

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0.2,11.11

0.167,22.20

0.167, 11.11

0.2,22.20

answer is A.

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Detailed Solution

$8 g NaOH, mol of NaOH = \frac{8}{40} = 0 .2 mol$
$18 g H_{2} O, mol of H_{2} O = \frac{18}{18} = 1 mol$
$∴ X_{NaOH} = \frac{0 .2}{1 .2} = 0 .167$
$Molality = \frac{0.2 \times 1000}{18} = 11.11 m$

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