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Q.

$8 \sin θ \cos θ \cos 2 θ \cos 4 θ =$

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a

$\sin 8 θ$

b

$\cos 8 θ$

c

$\sin 4 θ$

d

$\cos 4 θ$

answer is A.

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Detailed Solution

$8 \sin θ \cos θ \cos 2 θ \cos 4 θ$

$= 4 (2 \sin θ \cos θ) \cos 2 θ \cos 4 θ$

$= 4 \sin 2 θ \cos 2 θ \cos 4 θ$

. $= 2 (2 \sin 2 θ \cos 2 θ) \cos 4 θ$

$= 2 \sin 4 θ \cos 4 θ$

$= \sin 8 θ$

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