9.8 g of $H_{2}S{O}_4$ is present in two litre of a solution. The molarity of the solution is_______.

Given:
Mass of H₂SO₄ = 9.8 g
Volume of the solution = 2 L

First, we need to convert the mass of H₂SO₄ to moles using its molar mass. The molar mass of H₂SO₄ is approximately 98.09 g/mol.

Number of moles of H₂SO₄ = Mass of H2SO4 / Molar mass of H₂SO₄
Number of moles of H₂SO₄ = 9.8 g / 98.09 g/mol
Number of moles of H₂SO₄ = 0.1 mol

Next, we can calculate the molarity (M) using the formula:

Molarity (M) = Moles of solute / Volume of solution (in L)
Molarity (M) = 0.1 mol / 2 L
Molarity (M) = 0.05 M

Therefore, the molarity of the solution containing 9.8 g of H₂SO₄ in two liters of solution is 0.05 M.